3203200313413 has 4 divisors (see below), whose sum is σ = 3219296797600. Its totient is φ = 3187103829228.

The previous prime is 3203200313281. The next prime is 3203200313437. The reversal of 3203200313413 is 3143130023023.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3203200313413 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3203200319413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8048241795 + ... + 8048242192.

It is an arithmetic number, because the mean of its divisors is an integer number (804824199400).

Almost surely, 2^{3203200313413} is an apocalyptic number.

It is an amenable number.

3203200313413 is a deficient number, since it is larger than the sum of its proper divisors (16096484187).

3203200313413 is a wasteful number, since it uses less digits than its factorization.

3203200313413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16096484186.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 3203200313413 its reverse (3143130023023), we get a palindrome (6346330336436).

The spelling of 3203200313413 in words is "three trillion, two hundred three billion, two hundred million, three hundred thirteen thousand, four hundred thirteen".