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320327489363711 = 1718842793491983
BaseRepresentation
bin100100011010101100000111…
…0001101110001111011111111
31120000012000020111102111002212
41020311120032031301323333
5313441221144234114321
63053140230032011035
7124320616542255014
oct11065301615617377
91500160214374085
10320327489363711
1193080141909665
122bb15744090a7b
13109979a26c7a2b
145915d0ca2170b
1527076be3a055b
hex123560e371eff

320327489363711 has 4 divisors (see below), whose sum is σ = 339170282855712. Its totient is φ = 301484695871712.

The previous prime is 320327489363663. The next prime is 320327489363737. The reversal of 320327489363711 is 117363984723023.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-320327489363711 is a prime.

It is a super-4 number, since 4×3203274893637114 (a number of 59 digits) contains 4444 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (320327489363111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9421396745975 + ... + 9421396746008.

It is an arithmetic number, because the mean of its divisors is an integer number (84792570713928).

Almost surely, 2320327489363711 is an apocalyptic number.

320327489363711 is a deficient number, since it is larger than the sum of its proper divisors (18842793492001).

320327489363711 is a wasteful number, since it uses less digits than its factorization.

320327489363711 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18842793492000.

The product of its (nonzero) digits is 27433728, while the sum is 59.

The spelling of 320327489363711 in words is "three hundred twenty trillion, three hundred twenty-seven billion, four hundred eighty-nine million, three hundred sixty-three thousand, seven hundred eleven".

Divisors: 1 17 18842793491983 320327489363711