Base | Representation |
---|---|
bin | 1011111011111010… |
… | …1110010000100001 |
3 | 22021022002211100012 |
4 | 2332332232100201 |
5 | 23030223112231 |
6 | 1245535134305 |
7 | 142254341414 |
oct | 27676562041 |
9 | 8238084305 |
10 | 3204113441 |
11 | 13a4702941 |
12 | 755074395 |
13 | 3c0a7bc19 |
14 | 225779b7b |
15 | 13b461e2b |
hex | befae421 |
3204113441 has 2 divisors, whose sum is σ = 3204113442. Its totient is φ = 3204113440.
The previous prime is 3204113377. The next prime is 3204113443. The reversal of 3204113441 is 1443114023.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2247139216 + 956974225 = 47404^2 + 30935^2 .
It is a cyclic number.
It is not a de Polignac number, because 3204113441 - 26 = 3204113377 is a prime.
Together with 3204113443, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (3204113443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1602056720 + 1602056721.
It is an arithmetic number, because the mean of its divisors is an integer number (1602056721).
Almost surely, 23204113441 is an apocalyptic number.
It is an amenable number.
3204113441 is a deficient number, since it is larger than the sum of its proper divisors (1).
3204113441 is an equidigital number, since it uses as much as digits as its factorization.
3204113441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
The square root of 3204113441 is about 56604.8888436326. Note that the first 4 decimals coincide. The cubic root of 3204113441 is about 1474.2437476890.
Adding to 3204113441 its reverse (1443114023), we get a palindrome (4647227464).
The spelling of 3204113441 in words is "three billion, two hundred four million, one hundred thirteen thousand, four hundred forty-one".
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