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32100130113 = 323465219277
BaseRepresentation
bin11101111001010100…
…010001110101000001
310001212010001120021220
4131321110101311001
51011220113130423
622425133105253
72214320414112
oct357124216501
9101763046256
1032100130113
1112682760957
12627a328229
1330474ca23c
1417a732a209
15c7d1b99e3
hex779511d41

32100130113 has 8 divisors (see below), whose sum is σ = 44661050688. Its totient is φ = 20469648144.

The previous prime is 32100130109. The next prime is 32100130157. The reversal of 32100130113 is 31103100123.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 32100130113 - 22 = 32100130109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 32100130092 and 32100130101.

It is not an unprimeable number, because it can be changed into a prime (32100130313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 232609570 + ... + 232609707.

It is an arithmetic number, because the mean of its divisors is an integer number (5582631336).

Almost surely, 232100130113 is an apocalyptic number.

It is an amenable number.

32100130113 is a deficient number, since it is larger than the sum of its proper divisors (12560920575).

32100130113 is a wasteful number, since it uses less digits than its factorization.

32100130113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 465219303.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 32100130113 its reverse (31103100123), we get a palindrome (63203230236).

The spelling of 32100130113 in words is "thirty-two billion, one hundred million, one hundred thirty thousand, one hundred thirteen".

Divisors: 1 3 23 69 465219277 1395657831 10700043371 32100130113