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32100140013 = 310700046671
BaseRepresentation
bin11101111001010100…
…010100001111101101
310001212010002001212120
4131321110110033231
51011220113440023
622425133223153
72214320455014
oct357124241755
9101763061776
1032100140013
1112682768337
12627a331ab9
1330475018b6
1417a732da7b
15c7d1bc8e3
hex7795143ed

32100140013 has 4 divisors (see below), whose sum is σ = 42800186688. Its totient is φ = 21400093340.

The previous prime is 32100139979. The next prime is 32100140021. The reversal of 32100140013 is 31004100123.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 32100140013 - 26 = 32100139949 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 32100139974 and 32100140001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (32100140053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5350023333 + ... + 5350023338.

It is an arithmetic number, because the mean of its divisors is an integer number (10700046672).

Almost surely, 232100140013 is an apocalyptic number.

It is an amenable number.

32100140013 is a deficient number, since it is larger than the sum of its proper divisors (10700046675).

32100140013 is a wasteful number, since it uses less digits than its factorization.

32100140013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10700046674.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 32100140013 its reverse (31004100123), we get a palindrome (63104240136).

The spelling of 32100140013 in words is "thirty-two billion, one hundred million, one hundred forty thousand, thirteen".

Divisors: 1 3 10700046671 32100140013