Base | Representation |
---|---|
bin | 11101111001010100… |
… | …010100010010001101 |
3 | 10001212010002002002111 |
4 | 131321110110102031 |
5 | 1011220113441143 |
6 | 22425133224021 |
7 | 2214320455333 |
oct | 357124242215 |
9 | 101763062074 |
10 | 32100140173 |
11 | 12682768472 |
12 | 627a332011 |
13 | 30475019aa |
14 | 17a732db53 |
15 | c7d1bc99d |
hex | 77951448d |
32100140173 has 2 divisors, whose sum is σ = 32100140174. Its totient is φ = 32100140172.
The previous prime is 32100140077. The next prime is 32100140179. The reversal of 32100140173 is 37104100123.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 27901359369 + 4198780804 = 167037^2 + 64798^2 .
It is an emirp because it is prime and its reverse (37104100123) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-32100140173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32100140179) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16050070086 + 16050070087.
It is an arithmetic number, because the mean of its divisors is an integer number (16050070087).
Almost surely, 232100140173 is an apocalyptic number.
It is an amenable number.
32100140173 is a deficient number, since it is larger than the sum of its proper divisors (1).
32100140173 is an equidigital number, since it uses as much as digits as its factorization.
32100140173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 22.
Adding to 32100140173 its reverse (37104100123), we get a palindrome (69204240296).
The spelling of 32100140173 in words is "thirty-two billion, one hundred million, one hundred forty thousand, one hundred seventy-three".
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