32100201202013 has 4 divisors (see below), whose sum is σ = 36685944230880. Its totient is φ = 27514458173148.

The previous prime is 32100201202007. The next prime is 32100201202033. The reversal of 32100201202013 is 31020210200123.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 32100201202013 - 2⁴² = 27702154690909 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 32100201201982 and 32100201202000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (32100201202033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2292871514423 + ... + 2292871514436.

It is an arithmetic number, because the mean of its divisors is an integer number (9171486057720).

Almost surely, 2^{32100201202013} is an apocalyptic number.

It is an amenable number.

32100201202013 is a deficient number, since it is larger than the sum of its proper divisors (4585743028867).

32100201202013 is an equidigital number, since it uses as much as digits as its factorization.

32100201202013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4585743028866.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 32100201202013 its reverse (31020210200123), we get a palindrome (63120411402136).

The spelling of 32100201202013 in words is "thirty-two trillion, one hundred billion, two hundred one million, two hundred two thousand, thirteen".