Search a number
-
+
32103131230309 is a prime number
BaseRepresentation
bin1110100110010100101111…
…01110111011000001100101
311012200000210102010221011211
413103022113232323001211
513201434203043332214
6152135550324231421
76522242343032146
oct723122756730145
9135600712127154
1032103131230309
11a25795271a687
12372597583b571
1314bb40a124049
147cdb2aaa3acd
153aa121d580c4
hex1d3297bbb065

32103131230309 has 2 divisors, whose sum is σ = 32103131230310. Its totient is φ = 32103131230308.

The previous prime is 32103131230297. The next prime is 32103131230321. The reversal of 32103131230309 is 90303213130123.

It is a balanced prime because it is at equal distance from previous prime (32103131230297) and next prime (32103131230321).

It can be written as a sum of positive squares in only one way, i.e., 19519581101409 + 12583550128900 = 4418097^2 + 3547330^2 .

It is a cyclic number.

It is not a de Polignac number, because 32103131230309 - 25 = 32103131230277 is a prime.

It is a super-2 number, since 2×321031312303092 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32103131230399) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16051565615154 + 16051565615155.

It is an arithmetic number, because the mean of its divisors is an integer number (16051565615155).

Almost surely, 232103131230309 is an apocalyptic number.

It is an amenable number.

32103131230309 is a deficient number, since it is larger than the sum of its proper divisors (1).

32103131230309 is an equidigital number, since it uses as much as digits as its factorization.

32103131230309 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8748, while the sum is 31.

The spelling of 32103131230309 in words is "thirty-two trillion, one hundred three billion, one hundred thirty-one million, two hundred thirty thousand, three hundred nine".