Base | Representation |
---|---|
bin | 1001010110000111101… |
… | …01010110100111111011 |
3 | 1010200211220222211010121 |
4 | 10223003311112213323 |
5 | 20230114424421243 |
6 | 403303424354111 |
7 | 32125324340626 |
oct | 4530365264773 |
9 | 1120756884117 |
10 | 321113123323 |
11 | 114201a94353 |
12 | 52298175937 |
13 | 243860005a5 |
14 | 117831c0dbd |
15 | 85460041ed |
hex | 4ac3d569fb |
321113123323 has 2 divisors, whose sum is σ = 321113123324. Its totient is φ = 321113123322.
The previous prime is 321113123321. The next prime is 321113123329. The reversal of 321113123323 is 323321311123.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 321113123323 - 21 = 321113123321 is a prime.
It is a super-3 number, since 3×3211131233233 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 321113123321, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (321113123321) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160556561661 + 160556561662.
It is an arithmetic number, because the mean of its divisors is an integer number (160556561662).
Almost surely, 2321113123323 is an apocalyptic number.
321113123323 is a deficient number, since it is larger than the sum of its proper divisors (1).
321113123323 is an equidigital number, since it uses as much as digits as its factorization.
321113123323 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1944, while the sum is 25.
Adding to 321113123323 its reverse (323321311123), we get a palindrome (644434434446).
The spelling of 321113123323 in words is "three hundred twenty-one billion, one hundred thirteen million, one hundred twenty-three thousand, three hundred twenty-three".
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