Base | Representation |
---|---|
bin | 1110100110100101011101… |
… | …00100001000101010010100 |
3 | 11012200212221202101200121021 |
4 | 13103102232210020222110 |
5 | 13202111042134310030 |
6 | 152144032542330524 |
7 | 6523010610110020 |
oct | 723225644105224 |
9 | 135625852350537 |
10 | 32112104213140 |
11 | a260737738476 |
12 | 372765a889a44 |
13 | 14bc20a104c43 |
14 | 7d033c685380 |
15 | 3aa49999997a |
hex | 1d34ae908a94 |
32112104213140 has 48 divisors (see below), whose sum is σ = 81125315913600. Its totient is φ = 10430397758592.
The previous prime is 32112104213129. The next prime is 32112104213143. The reversal of 32112104213140 is 4131240121123.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (32112104213143) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6036107155 + ... + 6036112474.
It is an arithmetic number, because the mean of its divisors is an integer number (1690110748200).
Almost surely, 232112104213140 is an apocalyptic number.
It is an amenable number.
32112104213140 is an abundant number, since it is smaller than the sum of its proper divisors (49013211700460).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
32112104213140 is a wasteful number, since it uses less digits than its factorization.
32112104213140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12072219664 (or 12072219662 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 32112104213140 its reverse (4131240121123), we get a palindrome (36243344334263).
The spelling of 32112104213140 in words is "thirty-two trillion, one hundred twelve billion, one hundred four million, two hundred thirteen thousand, one hundred forty".
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