Base | Representation |
---|---|
bin | 11101111010000101… |
… | …110011000010100111 |
3 | 10001220000111002000011 |
4 | 131322011303002213 |
5 | 1011231424024312 |
6 | 22430315231051 |
7 | 2214535640632 |
oct | 357205630247 |
9 | 101800432004 |
10 | 32113111207 |
11 | 1268a017831 |
12 | 6282748487 |
13 | 304a0c3968 |
14 | 17a8d48c19 |
15 | c7e3d0da7 |
hex | 77a1730a7 |
32113111207 has 2 divisors, whose sum is σ = 32113111208. Its totient is φ = 32113111206.
The previous prime is 32113111187. The next prime is 32113111229. The reversal of 32113111207 is 70211131123.
It is an a-pointer prime, because the next prime (32113111229) can be obtained adding 32113111207 to its sum of digits (22).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 32113111207 - 211 = 32113109159 is a prime.
It is a super-2 number, since 2×321131112072 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32113114207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16056555603 + 16056555604.
It is an arithmetic number, because the mean of its divisors is an integer number (16056555604).
Almost surely, 232113111207 is an apocalyptic number.
32113111207 is a deficient number, since it is larger than the sum of its proper divisors (1).
32113111207 is an equidigital number, since it uses as much as digits as its factorization.
32113111207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 22.
The spelling of 32113111207 in words is "thirty-two billion, one hundred thirteen million, one hundred eleven thousand, two hundred seven".
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