Base | Representation |
---|---|
bin | 101110101110110010110… |
… | …011100001001111010010 |
3 | 102101000000211112222200221 |
4 | 232232302303201033102 |
5 | 410103311121420200 |
6 | 10455134110103254 |
7 | 451004003121160 |
oct | 56566263411722 |
9 | 12330024488627 |
10 | 3211340420050 |
11 | 1028a15a47354 |
12 | 43a4674aab2a |
13 | 1a3a9c4572a9 |
14 | b1603180230 |
15 | 5880359c91a |
hex | 2ebb2ce13d2 |
3211340420050 has 96 divisors (see below), whose sum is σ = 7396037016192. Its totient is φ = 1012165217280.
The previous prime is 3211340420009. The next prime is 3211340420063. The reversal of 3211340420050 is 500240431123.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a junction number, because it is equal to n+sod(n) for n = 3211340419997 and 3211340420024.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 6019977 + ... + 6531676.
It is an arithmetic number, because the mean of its divisors is an integer number (77042052252).
Almost surely, 23211340420050 is an apocalyptic number.
3211340420050 is an abundant number, since it is smaller than the sum of its proper divisors (4184696596142).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3211340420050 is a wasteful number, since it uses less digits than its factorization.
3211340420050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12551732 (or 12551727 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 3211340420050 its reverse (500240431123), we get a palindrome (3711580851173).
The spelling of 3211340420050 in words is "three trillion, two hundred eleven billion, three hundred forty million, four hundred twenty thousand, fifty".
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