Base | Representation |
---|---|
bin | 100100100001001000100001… |
… | …1010110101001100111010101 |
3 | 1120010022200021022010220211002 |
4 | 1021002101003112221213111 |
5 | 314100224004400104331 |
6 | 3055055140431353045 |
7 | 124441612103553401 |
oct | 11102210326514725 |
9 | 1503280238126732 |
10 | 321213144144341 |
11 | 93391802950859 |
12 | 30039314082785 |
13 | 10a303671a3a47 |
14 | 5946b28b4a101 |
15 | 27207573069cb |
hex | 12424435a99d5 |
321213144144341 has 2 divisors, whose sum is σ = 321213144144342. Its totient is φ = 321213144144340.
The previous prime is 321213144144329. The next prime is 321213144144353. The reversal of 321213144144341 is 143441441312123.
It is a balanced prime because it is at equal distance from previous prime (321213144144329) and next prime (321213144144353).
It can be written as a sum of positive squares in only one way, i.e., 274019885174116 + 47193258970225 = 16553546^2 + 6869735^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-321213144144341 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 321213144144295 and 321213144144304.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (321213144144311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160606572072170 + 160606572072171.
It is an arithmetic number, because the mean of its divisors is an integer number (160606572072171).
Almost surely, 2321213144144341 is an apocalyptic number.
It is an amenable number.
321213144144341 is a deficient number, since it is larger than the sum of its proper divisors (1).
321213144144341 is an equidigital number, since it uses as much as digits as its factorization.
321213144144341 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 110592, while the sum is 38.
Adding to 321213144144341 its reverse (143441441312123), we get a palindrome (464654585456464).
The spelling of 321213144144341 in words is "three hundred twenty-one trillion, two hundred thirteen billion, one hundred forty-four million, one hundred forty-four thousand, three hundred forty-one".
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