3212142000113 has 4 divisors (see below), whose sum is σ = 3351800347968. Its totient is φ = 3072483652260.

The previous prime is 3212142000097. The next prime is 3212142000139. The reversal of 3212142000113 is 3110002412123.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3212142000113 - 2⁴ = 3212142000097 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (3212142000143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69829173893 + ... + 69829173938.

It is an arithmetic number, because the mean of its divisors is an integer number (837950086992).

Almost surely, 2^{3212142000113} is an apocalyptic number.

It is an amenable number.

3212142000113 is a deficient number, since it is larger than the sum of its proper divisors (139658347855).

3212142000113 is a wasteful number, since it uses less digits than its factorization.

3212142000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 139658347854.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 3212142000113 its reverse (3110002412123), we get a palindrome (6322144412236).

The spelling of 3212142000113 in words is "three trillion, two hundred twelve billion, one hundred forty-two million, one hundred thirteen", and thus it is an aban number.