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32130000300511 is a prime number
BaseRepresentation
bin1110100111000110110010…
…10000010010100111011111
311012202121010222001010022001
413103203121100102213133
513202404220034104021
6152200152433503131
76524213234252611
oct723433120224737
9135677128033261
1032130000300511
11a2682905a6823
12372b014111aa7
1314c0acc951b59
147d1159382db1
153aab95b79091
hex1d38d94129df

32130000300511 has 2 divisors, whose sum is σ = 32130000300512. Its totient is φ = 32130000300510.

The previous prime is 32130000300479. The next prime is 32130000300523. The reversal of 32130000300511 is 11500300003123.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 32130000300511 - 25 = 32130000300479 is a prime.

It is a super-2 number, since 2×321300003005112 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32130000390511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16065000150255 + 16065000150256.

It is an arithmetic number, because the mean of its divisors is an integer number (16065000150256).

Almost surely, 232130000300511 is an apocalyptic number.

32130000300511 is a deficient number, since it is larger than the sum of its proper divisors (1).

32130000300511 is an equidigital number, since it uses as much as digits as its factorization.

32130000300511 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 270, while the sum is 19.

Adding to 32130000300511 its reverse (11500300003123), we get a palindrome (43630300303634).

The spelling of 32130000300511 in words is "thirty-two trillion, one hundred thirty billion, three hundred thousand, five hundred eleven".