Base | Representation |
---|---|
bin | 101110110000011100011… |
… | …101011101011101100111 |
3 | 102101011121101000111212112 |
4 | 232300130131131131213 |
5 | 410120423413203221 |
6 | 10500030031111235 |
7 | 451065636025613 |
oct | 56603435353547 |
9 | 12334541014775 |
10 | 3213113022311 |
11 | 10297455986a5 |
12 | 43a88107251b |
13 | 1a3cc277397a |
14 | b1730764343 |
15 | 588a8ee315b |
hex | 2ec1c75d767 |
3213113022311 has 4 divisors (see below), whose sum is σ = 3213200236992. Its totient is φ = 3213025807632.
The previous prime is 3213113022293. The next prime is 3213113022349. The reversal of 3213113022311 is 1132203113123.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3213113022311 - 238 = 2938235115367 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3213113024311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43552055 + ... + 43625768.
It is an arithmetic number, because the mean of its divisors is an integer number (803300059248).
Almost surely, 23213113022311 is an apocalyptic number.
3213113022311 is a deficient number, since it is larger than the sum of its proper divisors (87214681).
3213113022311 is an equidigital number, since it uses as much as digits as its factorization.
3213113022311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 87214680.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 3213113022311 its reverse (1132203113123), we get a palindrome (4345316135434).
The spelling of 3213113022311 in words is "three trillion, two hundred thirteen billion, one hundred thirteen million, twenty-two thousand, three hundred eleven".
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