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32140120054373 is a prime number
BaseRepresentation
bin1110100111011001101000…
…11100000101101001100101
311012210120021020010212211122
413103230310130011221211
513203040431213214443
6152204544535143325
76525022064612312
oct723546434055145
9135716236125748
1032140120054373
11a271603974671
123730b79214b45
1314c1a533ab1a6
147d1839399d09
153ab0892de968
hex1d3b34705a65

32140120054373 has 2 divisors, whose sum is σ = 32140120054374. Its totient is φ = 32140120054372.

The previous prime is 32140120054303. The next prime is 32140120054391. The reversal of 32140120054373 is 37345002104123.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29045395226884 + 3094724827489 = 5389378^2 + 1759183^2 .

It is a cyclic number.

It is not a de Polignac number, because 32140120054373 - 214 = 32140120037989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32140120054303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16070060027186 + 16070060027187.

It is an arithmetic number, because the mean of its divisors is an integer number (16070060027187).

Almost surely, 232140120054373 is an apocalyptic number.

It is an amenable number.

32140120054373 is a deficient number, since it is larger than the sum of its proper divisors (1).

32140120054373 is an equidigital number, since it uses as much as digits as its factorization.

32140120054373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60480, while the sum is 35.

Adding to 32140120054373 its reverse (37345002104123), we get a palindrome (69485122158496).

The spelling of 32140120054373 in words is "thirty-two trillion, one hundred forty billion, one hundred twenty million, fifty-four thousand, three hundred seventy-three".