Base | Representation |
---|---|
bin | 100100100010100100110000… |
… | …1110101110101000111100111 |
3 | 1120011000121112211120202211002 |
4 | 1021011021201311311013213 |
5 | 314112000141334130043 |
6 | 3055330140013103515 |
7 | 124462123521632126 |
oct | 11105114165650747 |
9 | 1504017484522732 |
10 | 321411224130023 |
11 | 93458809936865 |
12 | 3006b794787b9b |
13 | 10a45c437a2571 |
14 | 5952559c33abd |
15 | 272599be17bb8 |
hex | 1245261d751e7 |
321411224130023 has 2 divisors, whose sum is σ = 321411224130024. Its totient is φ = 321411224130022.
The previous prime is 321411224130019. The next prime is 321411224130067. The reversal of 321411224130023 is 320031422114123.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 321411224130023 - 22 = 321411224130019 is a prime.
It is a super-4 number, since 4×3214112241300234 (a number of 59 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (321411224130223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160705612065011 + 160705612065012.
It is an arithmetic number, because the mean of its divisors is an integer number (160705612065012).
Almost surely, 2321411224130023 is an apocalyptic number.
321411224130023 is a deficient number, since it is larger than the sum of its proper divisors (1).
321411224130023 is an equidigital number, since it uses as much as digits as its factorization.
321411224130023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 321411224130023 its reverse (320031422114123), we get a palindrome (641442646244146).
The spelling of 321411224130023 in words is "three hundred twenty-one trillion, four hundred eleven billion, two hundred twenty-four million, one hundred thirty thousand, twenty-three".
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