Base | Representation |
---|---|
bin | 101110110001100100000… |
… | …000010010000100111111 |
3 | 102101021201000121121200000 |
4 | 232301210000102010333 |
5 | 410130403203124210 |
6 | 10500345110005343 |
7 | 451140452350056 |
oct | 56614400220477 |
9 | 12337630547600 |
10 | 3214313333055 |
11 | 102a201096950 |
12 | 43ab57046853 |
13 | 1a4154346706 |
14 | b1805d3539d |
15 | 58929590ac0 |
hex | 2ec6401213f |
3214313333055 has 384 divisors, whose sum is σ = 6668573184000. Its totient is φ = 1470935531520.
The previous prime is 3214313333027. The next prime is 3214313333071. The reversal of 3214313333055 is 5503333134123.
3214313333055 is a `hidden beast` number, since 3 + 2 + 1 + 4 + 313 + 3 + 330 + 5 + 5 = 666.
It is not a de Polignac number, because 3214313333055 - 220 = 3214312284479 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 3459970831 + ... + 3459971759.
It is an arithmetic number, because the mean of its divisors is an integer number (17366076000).
Almost surely, 23214313333055 is an apocalyptic number.
3214313333055 is an abundant number, since it is smaller than the sum of its proper divisors (3454259850945).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3214313333055 is a wasteful number, since it uses less digits than its factorization.
3214313333055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1181 (or 1169 counting only the distinct ones).
The product of its (nonzero) digits is 145800, while the sum is 36.
Adding to 3214313333055 its reverse (5503333134123), we get a palindrome (8717646467178).
The spelling of 3214313333055 in words is "three trillion, two hundred fourteen billion, three hundred thirteen million, three hundred thirty-three thousand, fifty-five".
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