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3214520131 is a prime number
BaseRepresentation
bin1011111110011001…
…1010111101000011
322022000200112122011
42333212122331003
523040404121011
61250550153351
7142441653544
oct27746327503
98260615564
103214520131
1113aa570609
12758652857
133c2c83924
14226cc84cb
1513c31a621
hexbf99af43

3214520131 has 2 divisors, whose sum is σ = 3214520132. Its totient is φ = 3214520130.

The previous prime is 3214520129. The next prime is 3214520137. The reversal of 3214520131 is 1310254123.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 3214520131 - 21 = 3214520129 is a prime.

It is a super-2 number, since 2×32145201312 = 20666279345208514322, which contains 22 as substring.

Together with 3214520129, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (3214520137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1607260065 + 1607260066.

It is an arithmetic number, because the mean of its divisors is an integer number (1607260066).

Almost surely, 23214520131 is an apocalyptic number.

3214520131 is a deficient number, since it is larger than the sum of its proper divisors (1).

3214520131 is an equidigital number, since it uses as much as digits as its factorization.

3214520131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 22.

The square root of 3214520131 is about 56696.7382747897. The cubic root of 3214520131 is about 1475.8380959142.

Adding to 3214520131 its reverse (1310254123), we get a palindrome (4524774254).

The spelling of 3214520131 in words is "three billion, two hundred fourteen million, five hundred twenty thousand, one hundred thirty-one".