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32200203111997 is a prime number
BaseRepresentation
bin1110101001001001100011…
…01010110000111000111101
311020000022100112000110020011
413110210301222300320331
513210032003444040442
6152252322531423221
76532250023306444
oct724446152607075
9136008315013204
1032200203111997
11a295036221098
123740746a54b11
1314c760a0c93ab
147d46d8cadd5b
153ac903e9c117
hex1d4931ab0e3d

32200203111997 has 2 divisors, whose sum is σ = 32200203111998. Its totient is φ = 32200203111996.

The previous prime is 32200203111983. The next prime is 32200203112001. The reversal of 32200203111997 is 79911130200223.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18109331316036 + 14090871795961 = 4255506^2 + 3753781^2 .

It is a cyclic number.

It is not a de Polignac number, because 32200203111997 - 215 = 32200203079229 is a prime.

It is a super-2 number, since 2×322002031119972 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32200203111907) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16100101555998 + 16100101555999.

It is an arithmetic number, because the mean of its divisors is an integer number (16100101555999).

Almost surely, 232200203111997 is an apocalyptic number.

It is an amenable number.

32200203111997 is a deficient number, since it is larger than the sum of its proper divisors (1).

32200203111997 is an equidigital number, since it uses as much as digits as its factorization.

32200203111997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40824, while the sum is 40.

The spelling of 32200203111997 in words is "thirty-two trillion, two hundred billion, two hundred three million, one hundred eleven thousand, nine hundred ninety-seven".