Base | Representation |
---|---|
bin | 101110110110111101110… |
… | …000001100001100110101 |
3 | 102101211200021122121212221 |
4 | 232312331300030030311 |
5 | 410224243143001123 |
6 | 10503144443042341 |
7 | 451434266440066 |
oct | 56667560141465 |
9 | 12354607577787 |
10 | 3220114031413 |
11 | 1031708471434 |
12 | 4400b58103b1 |
13 | 1a486a040cc6 |
14 | b1bd64a456d |
15 | 58b6895b25d |
hex | 2edbdc0c335 |
3220114031413 has 2 divisors, whose sum is σ = 3220114031414. Its totient is φ = 3220114031412.
The previous prime is 3220114031383. The next prime is 3220114031417. The reversal of 3220114031413 is 3141304110223.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3216348122724 + 3765908689 = 1793418^2 + 61367^2 .
It is a cyclic number.
It is not a de Polignac number, because 3220114031413 - 237 = 3082675077941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3220114031417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1610057015706 + 1610057015707.
It is an arithmetic number, because the mean of its divisors is an integer number (1610057015707).
Almost surely, 23220114031413 is an apocalyptic number.
It is an amenable number.
3220114031413 is a deficient number, since it is larger than the sum of its proper divisors (1).
3220114031413 is an equidigital number, since it uses as much as digits as its factorization.
3220114031413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 3220114031413 its reverse (3141304110223), we get a palindrome (6361418141636).
The spelling of 3220114031413 in words is "three trillion, two hundred twenty billion, one hundred fourteen million, thirty-one thousand, four hundred thirteen".
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