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3220121120173 is a prime number
BaseRepresentation
bin101110110110111110001…
…011001110110110101101
3102101211200202222202211121
4232312332023032312231
5410224302001321143
610503145255020541
7451434413623036
oct56667613166655
912354622882747
103220121120173
111031711473311
124400b806a751
131a486b653739
14b1bd73cba8d
1558b693ab7ed
hex2edbe2cedad

3220121120173 has 2 divisors, whose sum is σ = 3220121120174. Its totient is φ = 3220121120172.

The previous prime is 3220121120137. The next prime is 3220121120213. The reversal of 3220121120173 is 3710211210223.

Together with previous prime (3220121120137) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1971098065764 + 1249023054409 = 1403958^2 + 1117597^2 .

It is a cyclic number.

It is not a de Polignac number, because 3220121120173 - 213 = 3220121111981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3220121123173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1610060560086 + 1610060560087.

It is an arithmetic number, because the mean of its divisors is an integer number (1610060560087).

Almost surely, 23220121120173 is an apocalyptic number.

It is an amenable number.

3220121120173 is a deficient number, since it is larger than the sum of its proper divisors (1).

3220121120173 is an equidigital number, since it uses as much as digits as its factorization.

3220121120173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 3220121120173 its reverse (3710211210223), we get a palindrome (6930332330396).

The spelling of 3220121120173 in words is "three trillion, two hundred twenty billion, one hundred twenty-one million, one hundred twenty thousand, one hundred seventy-three".