Base | Representation |
---|---|
bin | 101110110110111110001… |
… | …011001111100101100101 |
3 | 102101211200202222220221201 |
4 | 232312332023033211211 |
5 | 410224302001420143 |
6 | 10503145255042501 |
7 | 451434413634553 |
oct | 56667613174545 |
9 | 12354622886851 |
10 | 3220121123173 |
11 | 1031711475599 |
12 | 4400b8070431 |
13 | 1a486b654c06 |
14 | b1bd73ccbd3 |
15 | 58b693ac64d |
hex | 2edbe2cf965 |
3220121123173 has 2 divisors, whose sum is σ = 3220121123174. Its totient is φ = 3220121123172.
The previous prime is 3220121123117. The next prime is 3220121123239. The reversal of 3220121123173 is 3713211210223.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3119737973284 + 100383149889 = 1766278^2 + 316833^2 .
It is a cyclic number.
It is not a de Polignac number, because 3220121123173 - 29 = 3220121122661 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3220121120173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1610060561586 + 1610060561587.
It is an arithmetic number, because the mean of its divisors is an integer number (1610060561587).
Almost surely, 23220121123173 is an apocalyptic number.
It is an amenable number.
3220121123173 is a deficient number, since it is larger than the sum of its proper divisors (1).
3220121123173 is an equidigital number, since it uses as much as digits as its factorization.
3220121123173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 3220121123173 its reverse (3713211210223), we get a palindrome (6933332333396).
The spelling of 3220121123173 in words is "three trillion, two hundred twenty billion, one hundred twenty-one million, one hundred twenty-three thousand, one hundred seventy-three".
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