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3220323111997 is a prime number
BaseRepresentation
bin101110110111001010001…
…101110001010000111101
3102101212012212002000112021
4232313022031301100331
5410230210204040442
610503221312240141
7451442415544345
oct56671215612075
912355185060467
103220323111997
111031805496802
12440153840051
131a48a1457524
14b1c1616bd25
1558b7beaae67
hex2edca37143d

3220323111997 has 2 divisors, whose sum is σ = 3220323111998. Its totient is φ = 3220323111996.

The previous prime is 3220323111989. The next prime is 3220323112003. The reversal of 3220323111997 is 7991113230223.

3220323111997 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2006611069401 + 1213712042596 = 1416549^2 + 1101686^2 .

It is a cyclic number.

It is not a de Polignac number, because 3220323111997 - 23 = 3220323111989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3220323112997) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1610161555998 + 1610161555999.

It is an arithmetic number, because the mean of its divisors is an integer number (1610161555999).

Almost surely, 23220323111997 is an apocalyptic number.

It is an amenable number.

3220323111997 is a deficient number, since it is larger than the sum of its proper divisors (1).

3220323111997 is an equidigital number, since it uses as much as digits as its factorization.

3220323111997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 122472, while the sum is 43.

The spelling of 3220323111997 in words is "three trillion, two hundred twenty billion, three hundred twenty-three million, one hundred eleven thousand, nine hundred ninety-seven".