Base | Representation |
---|---|
bin | 11110000000000111… |
… | …110110000111110101 |
3 | 10002011001220120120221 |
4 | 132000013312013311 |
5 | 1011433330431123 |
6 | 22444332254341 |
7 | 2220205062154 |
oct | 360007660765 |
9 | 102131816527 |
10 | 32214311413 |
11 | 12731158a69 |
12 | 62b06113b1 |
13 | 306506783b |
14 | 17b856d59b |
15 | c8822125d |
hex | 7801f61f5 |
32214311413 has 2 divisors, whose sum is σ = 32214311414. Its totient is φ = 32214311412.
The previous prime is 32214311411. The next prime is 32214311471. The reversal of 32214311413 is 31411341223.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 23033222289 + 9181089124 = 151767^2 + 95818^2 .
It is a cyclic number.
It is not a de Polignac number, because 32214311413 - 21 = 32214311411 is a prime.
Together with 32214311411, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32214311411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16107155706 + 16107155707.
It is an arithmetic number, because the mean of its divisors is an integer number (16107155707).
Almost surely, 232214311413 is an apocalyptic number.
It is an amenable number.
32214311413 is a deficient number, since it is larger than the sum of its proper divisors (1).
32214311413 is an equidigital number, since it uses as much as digits as its factorization.
32214311413 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1728, while the sum is 25.
Adding to 32214311413 its reverse (31411341223), we get a palindrome (63625652636).
The spelling of 32214311413 in words is "thirty-two billion, two hundred fourteen million, three hundred eleven thousand, four hundred thirteen".
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