322212113 has 4 divisors (see below), whose sum is σ = 322271028. Its totient is φ = 322153200.

The previous prime is 322212097. The next prime is 322212131. The reversal of 322212113 is 311212223.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311212223 = 7 ⋅44458889.

It can be written as a sum of positive squares in 2 ways, for example, as 64192144 + 258019969 = 8012^2 + 16063^2 .

It is a cyclic number.

It is not a de Polignac number, because 322212113 - 2⁴ = 322212097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 322212091 and 322212100.

It is not an unprimeable number, because it can be changed into a prime (342212113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20306 + ... + 32507.

It is an arithmetic number, because the mean of its divisors is an integer number (80567757).

Almost surely, 2^322212113 is an apocalyptic number.

It is an amenable number.

322212113 is a deficient number, since it is larger than the sum of its proper divisors (58915).

322212113 is an equidigital number, since it uses as much as digits as its factorization.

322212113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58914.

The product of its digits is 144, while the sum is 17.

The square root of 322212113 is about 17950.2677695905. The cubic root of 322212113 is about 685.5628690950.

Adding to 322212113 its reverse (311212223), we get a palindrome (633424336).

It can be divided in two parts, 322 and 212113, that multiplied together give a palindrome (68300386).

The spelling of 322212113 in words is "three hundred twenty-two million, two hundred twelve thousand, one hundred thirteen".