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32234130545597 is a prime number
BaseRepresentation
bin1110101010001000101111…
…11001101001101110111101
311020010112220222110122122222
413111010113321221232331
513211110444404424342
6152320053302215125
76534560542606151
oct725042771515675
9136115828418588
1032234130545597
11a2a8466395112
1237472351244a5
1314ca8860561a6
147d61d6b7d061
153ad73c7b4ed2
hex1d5117e69bbd

32234130545597 has 2 divisors, whose sum is σ = 32234130545598. Its totient is φ = 32234130545596.

The previous prime is 32234130545509. The next prime is 32234130545599. The reversal of 32234130545597 is 79554503143223.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17301323784196 + 14932806761401 = 4159486^2 + 3864299^2 .

It is a cyclic number.

It is not a de Polignac number, because 32234130545597 - 210 = 32234130544573 is a prime.

Together with 32234130545599, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32234130545599) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16117065272798 + 16117065272799.

It is an arithmetic number, because the mean of its divisors is an integer number (16117065272799).

Almost surely, 232234130545597 is an apocalyptic number.

It is an amenable number.

32234130545597 is a deficient number, since it is larger than the sum of its proper divisors (1).

32234130545597 is an equidigital number, since it uses as much as digits as its factorization.

32234130545597 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13608000, while the sum is 53.

The spelling of 32234130545597 in words is "thirty-two trillion, two hundred thirty-four billion, one hundred thirty million, five hundred forty-five thousand, five hundred ninety-seven".