Base | Representation |
---|---|
bin | 1110101010010110001000… |
… | …00100011001010011101001 |
3 | 11020011020110121102110202220 |
4 | 13111023010010121103221 |
5 | 13211220202341312340 |
6 | 152323242152544253 |
7 | 6535233550214106 |
oct | 725130404312351 |
9 | 136136417373686 |
10 | 32241314010345 |
11 | a300512258540 |
12 | 37486ba9b2089 |
13 | 14cb45c37704b |
14 | 7d66b8c15aad |
15 | 3ada0d26ded0 |
hex | 1d52c41194e9 |
32241314010345 has 64 divisors (see below), whose sum is σ = 56684536473600. Its totient is φ = 15518615523840.
The previous prime is 32241314010329. The next prime is 32241314010391. The reversal of 32241314010345 is 54301041314223.
It is not a de Polignac number, because 32241314010345 - 24 = 32241314010329 is a prime.
It is a super-2 number, since 2×322413140103452 (a number of 28 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 404143621 + ... + 404223389.
It is an arithmetic number, because the mean of its divisors is an integer number (885695882400).
Almost surely, 232241314010345 is an apocalyptic number.
It is an amenable number.
32241314010345 is a deficient number, since it is larger than the sum of its proper divisors (24443222463255).
32241314010345 is a wasteful number, since it uses less digits than its factorization.
32241314010345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 97550.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 32241314010345 its reverse (54301041314223), we get a palindrome (86542355324568).
The spelling of 32241314010345 in words is "thirty-two trillion, two hundred forty-one billion, three hundred fourteen million, ten thousand, three hundred forty-five".
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