Base | Representation |
---|---|
bin | 1110101100000011011101… |
… | …01111111011000011010011 |
3 | 11020100211222101021111220020 |
4 | 13112001232233323003103 |
5 | 13213200411100403243 |
6 | 152410230513114523 |
7 | 6542412261015651 |
oct | 726015657730323 |
9 | 136324871244806 |
10 | 32300012122323 |
11 | a3233a3868890 |
12 | 3757b60858a43 |
13 | 1503b55187a9a |
14 | 7d9486815dd1 |
15 | 3b02e655c283 |
hex | 1d606ebfb0d3 |
32300012122323 has 64 divisors (see below), whose sum is σ = 50575850772480. Its totient is φ = 18129205036800.
The previous prime is 32300012122319. The next prime is 32300012122331. The reversal of 32300012122323 is 32322121000323.
It is not a de Polignac number, because 32300012122323 - 22 = 32300012122319 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 32300012122293 and 32300012122302.
It is not an unprimeable number, because it can be changed into a prime (32300012122333) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2568511 + ... + 8437847.
It is an arithmetic number, because the mean of its divisors is an integer number (790247668320).
Almost surely, 232300012122323 is an apocalyptic number.
32300012122323 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
32300012122323 is a deficient number, since it is larger than the sum of its proper divisors (18275838650157).
32300012122323 is a wasteful number, since it uses less digits than its factorization.
32300012122323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5869568.
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 32300012122323 its reverse (32322121000323), we get a palindrome (64622133122646).
The spelling of 32300012122323 in words is "thirty-two trillion, three hundred billion, twelve million, one hundred twenty-two thousand, three hundred twenty-three".
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