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32344044253 is a prime number
BaseRepresentation
bin11110000111110110…
…101111001011011101
310002111010000200120221
4132013312233023131
51012220033404003
622505245041341
72223341561053
oct360766571335
9102433020527
1032344044253
1112798408194
126327b56251
133085bbb831
1417cb8a01d3
15c947ea7bd
hex787daf2dd

32344044253 has 2 divisors, whose sum is σ = 32344044254. Its totient is φ = 32344044252.

The previous prime is 32344044217. The next prime is 32344044349. The reversal of 32344044253 is 35244044323.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31271678244 + 1072366009 = 176838^2 + 32747^2 .

It is an emirp because it is prime and its reverse (35244044323) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-32344044253 is a prime.

It is a super-2 number, since 2×323440442532 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32344041253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16172022126 + 16172022127.

It is an arithmetic number, because the mean of its divisors is an integer number (16172022127).

Almost surely, 232344044253 is an apocalyptic number.

It is an amenable number.

32344044253 is a deficient number, since it is larger than the sum of its proper divisors (1).

32344044253 is an equidigital number, since it uses as much as digits as its factorization.

32344044253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 138240, while the sum is 34.

Adding to 32344044253 its reverse (35244044323), we get a palindrome (67588088576).

The spelling of 32344044253 in words is "thirty-two billion, three hundred forty-four million, forty-four thousand, two hundred fifty-three".