Base | Representation |
---|---|
bin | 1110101101010101101010… |
… | …10010011100011011010101 |
3 | 11020112001220002112200200202 |
4 | 13112222311102130123111 |
5 | 13214411302141000010 |
6 | 152442410055150245 |
7 | 6545534033301461 |
oct | 726526522343325 |
9 | 136461802480622 |
10 | 32344145250005 |
11 | a340090868926 |
12 | 3764618975385 |
13 | 1508069601014 |
14 | 7db671cad4a1 |
15 | 3b152ad146a5 |
hex | 1d6ab549c6d5 |
32344145250005 has 24 divisors (see below), whose sum is σ = 39484314259200. Its totient is φ = 25435242047072.
The previous prime is 32344145249993. The next prime is 32344145250013. The reversal of 32344145250005 is 50005254144323.
It is not a de Polignac number, because 32344145250005 - 222 = 32344141055701 is a prime.
It is a super-2 number, since 2×323441452500052 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 361265636 + ... + 361355154.
It is an arithmetic number, because the mean of its divisors is an integer number (1645179760800).
Almost surely, 232344145250005 is an apocalyptic number.
It is an amenable number.
32344145250005 is a deficient number, since it is larger than the sum of its proper divisors (7140169009195).
32344145250005 is an equidigital number, since it uses as much as digits as its factorization.
32344145250005 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 110401 (or 110342 counting only the distinct ones).
The product of its (nonzero) digits is 288000, while the sum is 38.
Adding to 32344145250005 its reverse (50005254144323), we get a palindrome (82349399394328).
The spelling of 32344145250005 in words is "thirty-two trillion, three hundred forty-four billion, one hundred forty-five million, two hundred fifty thousand, five".
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