3240404120133 has 24 divisors (see below), whose sum is σ = 4751336346848. Its totient is φ = 2127626484192.

The previous prime is 3240404120119. The next prime is 3240404120183. The reversal of 3240404120133 is 3310214040423.

3240404120133 is a `hidden beast` number, since 3 + 2 + 4 + 0 + 404 + 120 + 133 = 666.

It is not a de Polignac number, because 3240404120133 - 2⁵ = 3240404120101 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3240404120097 and 3240404120106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3240404120113) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2721735 + ... + 3726747.

Almost surely, 2^{3240404120133} is an apocalyptic number.

It is an amenable number.

3240404120133 is a deficient number, since it is larger than the sum of its proper divisors (1510932226715).

3240404120133 is a wasteful number, since it uses less digits than its factorization.

3240404120133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1010433 (or 1010430 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 3240404120133 its reverse (3310214040423), we get a palindrome (6550618160556).

The spelling of 3240404120133 in words is "three trillion, two hundred forty billion, four hundred four million, one hundred twenty thousand, one hundred thirty-three".