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3245113400421 = 31081704466807
BaseRepresentation
bin101111001110001111110…
…101001101110001100101
3102111020012112101011010210
4233032033311031301211
5411131443012303141
610522441242210033
7453310635532614
oct57161765156145
912436175334123
103245113400421
111041276a07382
12444b11ab3919
131a70223b6249
14b30c872587b
155962d556916
hex2f38fd4dc65

3245113400421 has 4 divisors (see below), whose sum is σ = 4326817867232. Its totient is φ = 2163408933612.

The previous prime is 3245113400393. The next prime is 3245113400429. The reversal of 3245113400421 is 1240043115423.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 3245113400421 - 26 = 3245113400357 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3245113400429) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 540852233401 + ... + 540852233406.

It is an arithmetic number, because the mean of its divisors is an integer number (1081704466808).

Almost surely, 23245113400421 is an apocalyptic number.

It is an amenable number.

3245113400421 is a deficient number, since it is larger than the sum of its proper divisors (1081704466811).

3245113400421 is a wasteful number, since it uses less digits than its factorization.

3245113400421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1081704466810.

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 3245113400421 its reverse (1240043115423), we get a palindrome (4485156515844).

The spelling of 3245113400421 in words is "three trillion, two hundred forty-five billion, one hundred thirteen million, four hundred thousand, four hundred twenty-one".

Divisors: 1 3 1081704466807 3245113400421