Base | Representation |
---|---|
bin | 11110010001011101… |
… | …010100001010000011 |
3 | 10002220100011211001101 |
4 | 132101131110022003 |
5 | 1013032304332011 |
6 | 22533242115231 |
7 | 2230336143244 |
oct | 362135241203 |
9 | 102810154041 |
10 | 32505152131 |
11 | 128703469a1 |
12 | 6371aabb17 |
13 | 30b03a963a |
14 | 180503accb |
15 | ca3a212c1 |
hex | 791754283 |
32505152131 has 2 divisors, whose sum is σ = 32505152132. Its totient is φ = 32505152130.
The previous prime is 32505152111. The next prime is 32505152159. The reversal of 32505152131 is 13125150523.
It is an a-pointer prime, because the next prime (32505152159) can be obtained adding 32505152131 to its sum of digits (28).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 32505152131 - 213 = 32505143939 is a prime.
It is a super-3 number, since 3×325051521313 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 32505152131.
It is not a weakly prime, because it can be changed into another prime (32505152111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16252576065 + 16252576066.
It is an arithmetic number, because the mean of its divisors is an integer number (16252576066).
Almost surely, 232505152131 is an apocalyptic number.
32505152131 is a deficient number, since it is larger than the sum of its proper divisors (1).
32505152131 is an equidigital number, since it uses as much as digits as its factorization.
32505152131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4500, while the sum is 28.
The spelling of 32505152131 in words is "thirty-two billion, five hundred five million, one hundred fifty-two thousand, one hundred thirty-one".
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