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325155031413 = 3108385010471
BaseRepresentation
bin1001011101101001100…
…00000000100101110101
31011002021121120000200020
410232310300000211311
520311404142001123
6405212452435353
732330434110342
oct4566460004565
91132247500606
10325155031413
111159965a1763
1253025918b59
132487b506194
1411a47d237c9
1586d0ca67e3
hex4bb4c00975

325155031413 has 4 divisors (see below), whose sum is σ = 433540041888. Its totient is φ = 216770020940.

The previous prime is 325155031363. The next prime is 325155031423. The reversal of 325155031413 is 314130551523.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-325155031413 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (325155031423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54192505233 + ... + 54192505238.

It is an arithmetic number, because the mean of its divisors is an integer number (108385010472).

Almost surely, 2325155031413 is an apocalyptic number.

It is an amenable number.

325155031413 is a deficient number, since it is larger than the sum of its proper divisors (108385010475).

325155031413 is a wasteful number, since it uses less digits than its factorization.

325155031413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 108385010474.

The product of its (nonzero) digits is 27000, while the sum is 33.

Adding to 325155031413 its reverse (314130551523), we get a palindrome (639285582936).

The spelling of 325155031413 in words is "three hundred twenty-five billion, one hundred fifty-five million, thirty-one thousand, four hundred thirteen".

Divisors: 1 3 108385010471 325155031413