325314335 has 4 divisors (see below), whose sum is σ = 390377208. Its totient is φ = 260251464.

The previous prime is 325314299. The next prime is 325314361. The reversal of 325314335 is 533413523.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 533413523 = 257 ⋅2075539.

It is a cyclic number.

It is not a de Polignac number, because 325314335 - 2¹² = 325310239 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 325314298 and 325314307.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32531429 + ... + 32531438.

It is an arithmetic number, because the mean of its divisors is an integer number (97594302).

Almost surely, 2^325314335 is an apocalyptic number.

325314335 is a deficient number, since it is larger than the sum of its proper divisors (65062873).

325314335 is an equidigital number, since it uses as much as digits as its factorization.

325314335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65062872.

The product of its digits is 16200, while the sum is 29.

The square root of 325314335 is about 18036.4723546485. The cubic root of 325314335 is about 687.7560196897.

Adding to 325314335 its reverse (533413523), we get a palindrome (858727858).

The spelling of 325314335 in words is "three hundred twenty-five million, three hundred fourteen thousand, three hundred thirty-five".