325330993152 has 408 divisors, whose sum is σ = 1051143283008. Its totient is φ = 96101990400.

The previous prime is 325330993133. The next prime is 325330993153. The reversal of 325330993152 is 251399033523.

325330993152 is a `hidden beast` number, since 3 + 25 + 3 + 309 + 9 + 315 + 2 = 666.

It is a super-3 number, since 3×325330993152³ (a number of 36 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 325330993098 and 325330993107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (325330993153) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 266010013 + ... + 266011235.

It is an arithmetic number, because the mean of its divisors is an integer number (2576331576).

Almost surely, 2^325330993152 is an apocalyptic number.

325330993152 is a gapful number since it is divisible by the number (32) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 325330993152, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (525571641504).

325330993152 is an abundant number, since it is smaller than the sum of its proper divisors (725812289856).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

325330993152 is a wasteful number, since it uses less digits than its factorization.

325330993152 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1313 (or 1280 counting only the distinct ones).

The product of its (nonzero) digits is 656100, while the sum is 45.

The spelling of 325330993152 in words is "three hundred twenty-five billion, three hundred thirty million, nine hundred ninety-three thousand, one hundred fifty-two".