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32540094131 is a prime number
BaseRepresentation
bin11110010011100010…
…100110111010110011
310002222202221001110112
4132103202212322303
51013120231003011
622540531051535
72231242144046
oct362342467263
9102882831415
1032540094131
1112889042386
126381740bab
1330b76c1b8c
141809934c5d
15ca6b2458b
hex7938a6eb3

32540094131 has 2 divisors, whose sum is σ = 32540094132. Its totient is φ = 32540094130.

The previous prime is 32540094079. The next prime is 32540094133. The reversal of 32540094131 is 13149004523.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 32540094131 - 210 = 32540093107 is a prime.

It is a super-2 number, since 2×325400941312 (a number of 22 digits) contains 22 as substring.

Together with 32540094133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (32540094133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16270047065 + 16270047066.

It is an arithmetic number, because the mean of its divisors is an integer number (16270047066).

Almost surely, 232540094131 is an apocalyptic number.

32540094131 is a deficient number, since it is larger than the sum of its proper divisors (1).

32540094131 is an equidigital number, since it uses as much as digits as its factorization.

32540094131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 32.

Adding to 32540094131 its reverse (13149004523), we get a palindrome (45689098654).

The spelling of 32540094131 in words is "thirty-two billion, five hundred forty million, ninety-four thousand, one hundred thirty-one".