Base | Representation |
---|---|
bin | 11110010011100010… |
… | …100110111010110101 |
3 | 10002222202221001110121 |
4 | 132103202212322311 |
5 | 1013120231003013 |
6 | 22540531051541 |
7 | 2231242144051 |
oct | 362342467265 |
9 | 102882831417 |
10 | 32540094133 |
11 | 12889042388 |
12 | 6381740bb1 |
13 | 30b76c1b91 |
14 | 1809934c61 |
15 | ca6b2458d |
hex | 7938a6eb5 |
32540094133 has 2 divisors, whose sum is σ = 32540094134. Its totient is φ = 32540094132.
The previous prime is 32540094131. The next prime is 32540094143. The reversal of 32540094133 is 33149004523.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 28675358244 + 3864735889 = 169338^2 + 62167^2 .
It is a cyclic number.
It is not a de Polignac number, because 32540094133 - 21 = 32540094131 is a prime.
Together with 32540094131, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32540094131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16270047066 + 16270047067.
It is an arithmetic number, because the mean of its divisors is an integer number (16270047067).
Almost surely, 232540094133 is an apocalyptic number.
It is an amenable number.
32540094133 is a deficient number, since it is larger than the sum of its proper divisors (1).
32540094133 is an equidigital number, since it uses as much as digits as its factorization.
32540094133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 34.
Adding to 32540094133 its reverse (33149004523), we get a palindrome (65689098656).
The spelling of 32540094133 in words is "thirty-two billion, five hundred forty million, ninety-four thousand, one hundred thirty-three".
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