Base | Representation |
---|---|
bin | 1001011110001000010… |
… | …00100011011101000011 |
3 | 1011002221121012111000111 |
4 | 10233010020203131003 |
5 | 20312421224431112 |
6 | 405254232332151 |
7 | 32340016625524 |
oct | 4570410433503 |
9 | 1132847174014 |
10 | 325413123907 |
11 | 116009252443 |
12 | 53098244057 |
13 | 248bcb20131 |
14 | 11a7030884b |
15 | 86e87885a7 |
hex | 4bc4223743 |
325413123907 has 2 divisors, whose sum is σ = 325413123908. Its totient is φ = 325413123906.
The previous prime is 325413123877. The next prime is 325413123941. The reversal of 325413123907 is 709321314523.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-325413123907 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 325413123907.
It is not a weakly prime, because it can be changed into another prime (325413153907) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162706561953 + 162706561954.
It is an arithmetic number, because the mean of its divisors is an integer number (162706561954).
Almost surely, 2325413123907 is an apocalyptic number.
325413123907 is a deficient number, since it is larger than the sum of its proper divisors (1).
325413123907 is an equidigital number, since it uses as much as digits as its factorization.
325413123907 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 136080, while the sum is 40.
The spelling of 325413123907 in words is "three hundred twenty-five billion, four hundred thirteen million, one hundred twenty-three thousand, nine hundred seven".
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