Base | Representation |
---|---|
bin | 101111010110111011110… |
… | …100110000010000100111 |
3 | 102112010021121200012221011 |
4 | 233112323310300100213 |
5 | 411310044000132443 |
6 | 10531023022003051 |
7 | 454061043366553 |
oct | 57267364602047 |
9 | 12463247605834 |
10 | 3254441411623 |
11 | 1045223374246 |
12 | 446895a16487 |
13 | 1a7b7aac0cbc |
14 | b3731522863 |
15 | 599c7426b9d |
hex | 2f5bbd30427 |
3254441411623 has 2 divisors, whose sum is σ = 3254441411624. Its totient is φ = 3254441411622.
The previous prime is 3254441411609. The next prime is 3254441411633. The reversal of 3254441411623 is 3261141444523.
It is a strong prime.
It is an emirp because it is prime and its reverse (3261141444523) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3254441411623 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3254441411633) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1627220705811 + 1627220705812.
It is an arithmetic number, because the mean of its divisors is an integer number (1627220705812).
Almost surely, 23254441411623 is an apocalyptic number.
3254441411623 is a deficient number, since it is larger than the sum of its proper divisors (1).
3254441411623 is an equidigital number, since it uses as much as digits as its factorization.
3254441411623 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 276480, while the sum is 40.
The spelling of 3254441411623 in words is "three trillion, two hundred fifty-four billion, four hundred forty-one million, four hundred eleven thousand, six hundred twenty-three".
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