Base | Representation |
---|---|
bin | 100101000111000010110010… |
… | …1100010111010011000001101 |
3 | 1120210202210010212120222020121 |
4 | 1022032011211202322120031 |
5 | 320241110323324123000 |
6 | 3114124520341144541 |
7 | 125520214645220260 |
oct | 11216054542723015 |
9 | 1523683125528217 |
10 | 326423513114125 |
11 | 95010486344a29 |
12 | 3073b0920bb151 |
13 | 1101a7b384004b |
14 | 5a86da7740cd7 |
15 | 27b105843eb1a |
hex | 128e1658ba60d |
326423513114125 has 64 divisors (see below), whose sum is σ = 466469762863104. Its totient is φ = 223402360392000.
The previous prime is 326423513114093. The next prime is 326423513114131. The reversal of 326423513114125 is 521411315324623.
It is not a de Polignac number, because 326423513114125 - 25 = 326423513114093 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3031171032 + ... + 3031278718.
It is an arithmetic number, because the mean of its divisors is an integer number (7288590044736).
Almost surely, 2326423513114125 is an apocalyptic number.
326423513114125 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
It is an amenable number.
326423513114125 is a deficient number, since it is larger than the sum of its proper divisors (140046249748979).
326423513114125 is a wasteful number, since it uses less digits than its factorization.
326423513114125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 114347 (or 114337 counting only the distinct ones).
The product of its digits is 518400, while the sum is 43.
Adding to 326423513114125 its reverse (521411315324623), we get a palindrome (847834828438748).
The spelling of 326423513114125 in words is "three hundred twenty-six trillion, four hundred twenty-three billion, five hundred thirteen million, one hundred fourteen thousand, one hundred twenty-five".
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