Base | Representation |
---|---|
bin | 1110111001010011100000… |
… | …10110101101010000110111 |
3 | 11021222101011120021120211201 |
4 | 13130221300112231100313 |
5 | 13243130331213200210 |
6 | 153355325112313331 |
7 | 6620331002513263 |
oct | 734516026552067 |
9 | 137871146246751 |
10 | 32755305600055 |
11 | a4894a109a415 |
12 | 38102456a2847 |
13 | 1537a7314a88c |
14 | 8135183630a3 |
15 | 3bc0923c353a |
hex | 1dca705ad437 |
32755305600055 has 4 divisors (see below), whose sum is σ = 39306366720072. Its totient is φ = 26204244480040.
The previous prime is 32755305600053. The next prime is 32755305600077. The reversal of 32755305600055 is 55000650355723.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 32755305600055 - 21 = 32755305600053 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 32755305599978 and 32755305600014.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (32755305600053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3275530560001 + ... + 3275530560010.
It is an arithmetic number, because the mean of its divisors is an integer number (9826591680018).
Almost surely, 232755305600055 is an apocalyptic number.
32755305600055 is a deficient number, since it is larger than the sum of its proper divisors (6551061120017).
32755305600055 is an equidigital number, since it uses as much as digits as its factorization.
32755305600055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6551061120016.
The product of its (nonzero) digits is 2362500, while the sum is 46.
Adding to 32755305600055 its reverse (55000650355723), we get a palindrome (87755955955778).
The spelling of 32755305600055 in words is "thirty-two trillion, seven hundred fifty-five billion, three hundred five million, six hundred thousand, fifty-five".
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