Base | Representation |
---|---|
bin | 110000000001011000000… |
… | …111000010000111011101 |
3 | 102200110220120212222012201 |
4 | 300001120013002013131 |
5 | 413031411324401023 |
6 | 11004001033531501 |
7 | 460263254501146 |
oct | 60013007020735 |
9 | 12613816788181 |
10 | 3300013122013 |
11 | 1062589415813 |
12 | 453693873b91 |
13 | 1ac2612a43ca |
14 | b5a15a92acd |
15 | 5ac93145bad |
hex | 300581c21dd |
3300013122013 has 2 divisors, whose sum is σ = 3300013122014. Its totient is φ = 3300013122012.
The previous prime is 3300013121989. The next prime is 3300013122019. The reversal of 3300013122013 is 3102213100033.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3191289270724 + 108723851289 = 1786418^2 + 329733^2 .
It is a cyclic number.
It is not a de Polignac number, because 3300013122013 - 25 = 3300013121981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3300013122019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1650006561006 + 1650006561007.
It is an arithmetic number, because the mean of its divisors is an integer number (1650006561007).
Almost surely, 23300013122013 is an apocalyptic number.
It is an amenable number.
3300013122013 is a deficient number, since it is larger than the sum of its proper divisors (1).
3300013122013 is an equidigital number, since it uses as much as digits as its factorization.
3300013122013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 3300013122013 its reverse (3102213100033), we get a palindrome (6402226222046).
The spelling of 3300013122013 in words is "three trillion, three hundred billion, thirteen million, one hundred twenty-two thousand, thirteen".
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