Base | Representation |
---|---|
bin | 110000000001011110000… |
… | …000001110100100011110 |
3 | 102200111011110221120002220 |
4 | 300001132000032210132 |
5 | 413032112133020220 |
6 | 11004014525130210 |
7 | 460265565115035 |
oct | 60013600164436 |
9 | 12614143846086 |
10 | 3300112001310 |
11 | 106262a211243 |
12 | 4537009b9966 |
13 | 1ac278914a77 |
14 | b5a24c7171c |
15 | 5ac9bb78540 |
hex | 3005e00e91e |
3300112001310 has 32 divisors (see below), whose sum is σ = 7920480886272. Its totient is φ = 880006302240.
The previous prime is 3300112001309. The next prime is 3300112001311. The reversal of 3300112001310 is 131002110033.
It is an interprime number because it is at equal distance from previous prime (3300112001309) and next prime (3300112001311).
It is a super-2 number, since 2×33001120013102 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 3300112001310.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3300112001311) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 318954 + ... + 2588813.
It is an arithmetic number, because the mean of its divisors is an integer number (247515027696).
Almost surely, 23300112001310 is an apocalyptic number.
3300112001310 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
3300112001310 is an abundant number, since it is smaller than the sum of its proper divisors (4620368884962).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3300112001310 is a wasteful number, since it uses less digits than its factorization.
3300112001310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2945608.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 3300112001310 its reverse (131002110033), we get a palindrome (3431114111343).
The spelling of 3300112001310 in words is "three trillion, three hundred billion, one hundred twelve million, one thousand, three hundred ten".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •