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330013310117 is a prime number
BaseRepresentation
bin1001100110101100101…
…00110111110010100101
31011112211012021011011112
410303112110313302211
520401331401410432
6411334522314405
732562015565241
oct4632624676245
91145735234145
10330013310117
11117a59a01427
1253b60958a05
1325173ba40ca
1411d89253421
1588b75667b2
hex4cd6537ca5

330013310117 has 2 divisors, whose sum is σ = 330013310118. Its totient is φ = 330013310116.

The previous prime is 330013310023. The next prime is 330013310183. The reversal of 330013310117 is 711013310033.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 266007346081 + 64005964036 = 515759^2 + 252994^2 .

It is a cyclic number.

It is not a de Polignac number, because 330013310117 - 216 = 330013244581 is a prime.

It is a super-4 number, since 4×3300133101174 (a number of 47 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 330013310092 and 330013310101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (330013340117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165006655058 + 165006655059.

It is an arithmetic number, because the mean of its divisors is an integer number (165006655059).

Almost surely, 2330013310117 is an apocalyptic number.

It is an amenable number.

330013310117 is a deficient number, since it is larger than the sum of its proper divisors (1).

330013310117 is an equidigital number, since it uses as much as digits as its factorization.

330013310117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 567, while the sum is 23.

The spelling of 330013310117 in words is "three hundred thirty billion, thirteen million, three hundred ten thousand, one hundred seventeen".