Base | Representation |
---|---|
bin | 100101100001010100000110… |
… | …1111100111011001100011100 |
3 | 1121021112221201122120102101001 |
4 | 1023002220031330323030130 |
5 | 321224234324411043030 |
6 | 3125531324425200044 |
7 | 126342114636161362 |
oct | 11302501574731434 |
9 | 1537487648512331 |
10 | 330034111034140 |
11 | 96182753786387 |
12 | 310229a4030024 |
13 | 11220110835826 |
14 | 5b6da44205632 |
15 | 2824e2811acca |
hex | 12c2a0df3b31c |
330034111034140 has 48 divisors (see below), whose sum is σ = 693434103433344. Its totient is φ = 131944613299200.
The previous prime is 330034111034137. The next prime is 330034111034183. The reversal of 330034111034140 is 41430111430033.
It is a junction number, because it is equal to n+sod(n) for n = 330034111034099 and 330034111034108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 496287460 + ... + 496952020.
It is an arithmetic number, because the mean of its divisors is an integer number (14446543821528).
Almost surely, 2330034111034140 is an apocalyptic number.
It is an amenable number.
330034111034140 is an abundant number, since it is smaller than the sum of its proper divisors (363399992399204).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
330034111034140 is a wasteful number, since it uses less digits than its factorization.
330034111034140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 677518 (or 677516 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 330034111034140 its reverse (41430111430033), we get a palindrome (371464222464173).
The spelling of 330034111034140 in words is "three hundred thirty trillion, thirty-four billion, one hundred eleven million, thirty-four thousand, one hundred forty".
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