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330100230219119 is a prime number
BaseRepresentation
bin100101100001110010111001…
…0111101100110010101101111
31121021210021101121111000211222
41023003211302331212111233
5321231330232414002434
63130021541404533555
7126346645301032463
oct11303456275462557
91537707347430758
10330100230219119
11961a87a3299708
12310337772512bb
1311226419c5b719
145b72d176504a3
1528269e7b9a72e
hex12c3972f6656f

330100230219119 has 2 divisors, whose sum is σ = 330100230219120. Its totient is φ = 330100230219118.

The previous prime is 330100230219007. The next prime is 330100230219121. The reversal of 330100230219119 is 911912032001033.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-330100230219119 is a prime.

It is a super-2 number, since 2×3301002302191192 (a number of 30 digits) contains 22 as substring.

Together with 330100230219121, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (330100230213119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165050115109559 + 165050115109560.

It is an arithmetic number, because the mean of its divisors is an integer number (165050115109560).

Almost surely, 2330100230219119 is an apocalyptic number.

330100230219119 is a deficient number, since it is larger than the sum of its proper divisors (1).

330100230219119 is an equidigital number, since it uses as much as digits as its factorization.

330100230219119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8748, while the sum is 35.

The spelling of 330100230219119 in words is "three hundred thirty trillion, one hundred billion, two hundred thirty million, two hundred nineteen thousand, one hundred nineteen".