3304012433 has 2 divisors, whose sum is σ = 3304012434. Its totient is φ = 3304012432.

The previous prime is 3304012417. The next prime is 3304012483. The reversal of 3304012433 is 3342104033.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2202237184 + 1101775249 = 46928^2 + 33193^2 .

It is a cyclic number.

It is not a de Polignac number, because 3304012433 - 2⁴ = 3304012417 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3304012399 and 3304012408.

It is not a weakly prime, because it can be changed into another prime (3304012403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1652006216 + 1652006217.

It is an arithmetic number, because the mean of its divisors is an integer number (1652006217).

Almost surely, 2^3304012433 is an apocalyptic number.

It is an amenable number.

3304012433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3304012433 is an equidigital number, since it uses as much as digits as its factorization.

3304012433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 23.

The square root of 3304012433 is about 57480.5396025472. The cubic root of 3304012433 is about 1489.4087158865.

Adding to 3304012433 its reverse (3342104033), we get a palindrome (6646116466).

The spelling of 3304012433 in words is "three billion, three hundred four million, twelve thousand, four hundred thirty-three".